According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/
.
Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/
= 13.8 N
Hope this helps!
Answer:
a) 1955.6 J
b) 1955.6 J
c) 2607 N
d) 110373 J
Explanation:
a)
b) Work done on bullet should be increase in KE = 1955.6 J
c) Work done = Force \times displacement = KE of bullet
d) Work done to stop
Answer:
W = 270.9 J
Explanation:
given,
F(x) = (12.9 N/m²) x²
work = Force x displacement
dW = F .dx
the push-rod moves from x₁= 1 m to x₂ = 4 m
integrating the above
`
W = 270.9 J
work done by the motor is W = 270.9 J
Answer:
8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus
0.5333
Explanation:
Answer:
Option C. Rate of change of velocity
Explanation:
To know the correct answer to the question, it is important we know the definition of power.
Power can be defined as the rate at which work is done. Mathematically, it is expressed as:
Power = work / time
Work and energy has the same unit of measurement i.e joule. Thus, power can also be defined as the rate at which energy is transferred i.e
Power = enery / time
Energy is measured in Joules and time in second. Thus, power can also be defined as amount of joules transfered per second.
Power = Joule / sec
The rate of change of velocity on the other hand is termed acceleration.
Thus, the answer to the question is option C.