The formula for the force of gravity has ( M₁ · M₂ / D² ) in it.
After the changes, the new force will have ( 0.5M₁ · 0.5M₂ / (0.5D)² ) .
We can separate the new numbers from the original force, like this:
( 0.5M₁ · 0.5M₂ / (0.5D)² )
= ( 0.5 · 0.5 / (0.5)² ) times ( M₁ · M₂ / D² )
The first factor boils down to ' 1 '. So, those changes would
leave the strength of the force unchanged.
That's what I think.
Answer:
As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.
The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.
At that point by Newton's All inclusive Law of Attractive energy;
F=GMm/R^2
Mm= result of the majority
R=Distance Between the two masses by focus.
On the off chance that R is multiplied, new force=GMm/(2R)^2
=GMm/4R^2
Unique Power/New Force=4/1
F/4=New Power
Answer:
I finish that module I'm sure it's D
True. No matter can be created nor destroyed in pretty much every aspect of life, especially chemical reactions.
Answer:
Average speed of car in the first trip is 10 km/hr
Explanation:
It is given that first the car drives 6 hours to the east
Then travels 12 km to west in 3 hours
Average speed for the entire trip = 8 km/hr
Total time = 3+6 = 9 hour
So distance traveled in 9 hour = 9×8 = 72 km
As the car travel 12 km in west so distance traveled in east = 72-12 = 60 km
Time by which car traveled in east = 6 hour
So speed 
So average speed of car in the first trip is 10 km/hr