Answer:
1. 9x+4<58
x<6
2. 1x-2>3
x>1
Step-by-step explanation:
1. 9x+4<58
First, you need to group all the like terms ( the group of numbers that have the same variable), Also remember that, when a positive number crosses an inequality symbol, it becomes negative.
9x<58-4
Then, subtract the two numbers.
9x<54
Divide x's coefficient by 54 and you have your answer.
x<6
2. 1x-2>3
First, you need to group all the like terms. Remember that, when a negative number crosses an inequality symbol, it becomes positive.
1x>3-2
Then, subtract the two numbers.
1x>1
1 divided by one is one, so
x>1
Answer:
Step-by-step explanation:
it's 12 by 10, 12 x 10 = 120. because it's a triangle, you divide 120 by 2.
120 / 2 = 60. therefore the area of the triangle is 60. I also don't know the unit im supposed to use. is it centimeters? inches? miles?
Hello there!
1. Okay. So 70% is positive, so it is a corresponding growth. 70% is 0.7 in decimal form. C and D are both eliminated, because that's too large. When something grows by 70%, that is less than double. 0.7 is not right either, because that's more of a decay than a growth. The only answer that makes sense id 1.70, because you are going up, and adding 1 to decimal form brings you to the decimal that when multiplied will bring you to the total. The answer is B: 1.70.
2. So, -75% is negative, so it is a decay factor. A is eliminated, because it makes no sense and B is out, because that represents growth, not decay. You lose 75% of the amount overtime compounded, but you still have 25% that remains. To find that amount, you would subtract that amount from 1 to get the decay. 1 - 0.75 is 0.25. The decay factor is 0.25. The answer is D: 0.25.
Answer: 48 tickets
Step-by-step explanation:
Since the expression that gives the number of tickets a player wins if he shoots the ball in the hoop t times is expressed as 3t.
Therefore, the number of tickets that a player wins if he shoots the ball in the hoop 16 times will be:
= 3t
where,
t = 16
Therefore, 3t = 3 × 16 = 48
The player wins 48 tickets.
