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liberstina [14]
3 years ago
13

Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to

find the approximate surface area of the star.
Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

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The best player on a basketball team makes 85% of all free throws. The second-best player makes
xxTIMURxx [149]

Answer:

i. Estimated number of free throws of the best player = 0.85 * 40

ii. 34 free throws

Step-by-step explanation:

Percentage of free throws made by the best player = 85%

Percentage of free throws made by the second best player = 75%

Percentage of free throws made by the third best player = 70%

Therefore, for 40 attempts;

i. Estimated number of free throws made by the best player = 85% x 40

                                                         = 0.85 x 40

                                                         = 34

ii. Estimated number of free throws made by the second best player = 75%x 40

                                                                 = 0.75 x 40

                                                                 = 30

iii. Estimated number of free throws made by the third best player = 70% x 40

                                                                   = 0.70 x 40

                                                                   = 28

Thus, the equation that gives the estimated number of free throws is 0.85 * 40.

The best player will make about 34 free throws.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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The answer is C 26

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