<h3>Given:</h3>
<h3>Volume of the cone:</h3>



<h3>Volume of the cylinder:</h3>



<h3>Total volume:</h3>


<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>4188.7</u><u>9</u><u> </u><u>cubic</u><u> </u><u>centimeters</u><u>.</u>
Answer:
C. y - 5= 5/3 ( x - 3 )
Step-by-step explanation:
I used a graphing calculator
Answer:
4x?y*[2x2y)
Step-by-step explanation:
Answer:
Answer (B) and (D)
Step-by-step explanation:
First we need to figure out: What is quadrant II about?
As said in the picture provided, quadrant II is in the upper left corner of a graph.
For a point to be in QII, the <em>x values need to be negative</em>, and <em>the y values need to be positive</em>.
B: (-4,2) and D: (-3,5) would belong in QII.
<em>Their x values are negative, and the y values are positive. </em>
<em>Therefore, </em><em>B and D would be the correct answers.</em>
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