6×10^4
We use 6 because the # has to be greater than or equal to 1 but less than or equal to 10.
10^4=10000
10000×6=60000
Q: Reflect B (2,7) over the y-axis
Answer:
(-2,7)
Hope this helps! Feel free to comment on this reply if you have any questions. :)
Answer:
y = -2x + 5
Please Mark Brainliest If This Helped!
Answer:
Question 1: 4.5(10^−7)(2(10^4))
=
9/1000
(Decimal: 0.009)
Question 2:
mass of neutron/mass of electron = 2*10-24/(9*10-28)
2x10^(-24)/9x10^(-28)
d is closest.
Question 3:
4(10^3)(12(10^5))
=4000*1200000
=4*1000*12*100000
=(4*12)*(1000*100000)
=48*100000000
=4800000000
And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em><em>if</em><em> </em><em>so</em><em> </em><em>pls</em><em> </em><em>mark</em><em> </em><em>brainliest</em><em> </em><em>and</em><em> </em><em>heart</em><em>/</em><em>rate</em><em>!</em>
Answer:
242
Step-by-step explanation:
Simplify the following:
11 ((9^2 - 5^2)/2^2 + 8)
Hint: | Evaluate 2^2.
2^2 = 4:
11 ((9^2 - 5^2)/4 + 8)
Hint: | Evaluate 5^2.
5^2 = 25:
11 ((9^2 - 25)/4 + 8)
Hint: | Evaluate 9^2.
9^2 = 81:
11 ((81 - 25)/4 + 8)
Hint: | Subtract 25 from 81.
| 7 | 11
| 8 | 1
- | 2 | 5
| 5 | 6:
11 (56/4 + 8)
Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.
The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:
11 (14 + 8)
Hint: | Evaluate 14 + 8 using long addition.
| 1 |
| 1 | 4
+ | | 8
| 2 | 2:
11×22
Hint: | Multiply 11 and 22 together.
| 2 | 2
× | 1 | 1
| 2 | 2
2 | 2 | 0
2 | 4 | 2:
Answer: 242