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max2010maxim [7]
3 years ago
14

SOMEONE, PLEASE HELP!!!!!!

Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

I think its y^-3

Step-by-step explanation:

Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3

then using rules of exponents you would subtract the exponents witch would be y^-3

katovenus [111]3 years ago
6 0

Answer:

\frac{1}{y^{3} }

Step-by-step explanation:

\frac{y^{-5}}{y^{-2}}

Apply exponent rule \frac{x^a}{x^b}=x^{a-b}

=y^{-5-\left(-2\right)}

Apply rule -\left(-a\right)=a

=y^{-5+2}

Add/Subtract the numbers -5+2=-3

=y^{-3}

Apply exponent rule a^{-b}=\frac{1}{a^b}

=\frac{1}{y^3}

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In triangle bcd if bc =bd angle b = 13x-35 angle c =5x-19 and angled d = 2x+14 find x and the measure of each angle
MakcuM [25]

Answer:

<b = 108 degrees

<c = 36 degrees

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Step-by-step explanation:

The sum of angle in a triangle is 180 degrees

Hence <b + <c + <d = 180

13x-35 + 5x - 19 + 2x + 14 = 180

13x+5x+2x-35-19+14 = 180

20x-40 = 180

20x = 180 + 40

20 x = 220

x = 220/20

x = 11

Get <b

<b = 13x-35

<b = 13(11) - 35

<b = 143-35

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Get <c

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<c = 5(11)-19

<c = 55-19

<c = 36degrees

Get <d

<d = 2x+14

<d = 2(11) + 14

<d = 22+14

<d = 36 degrees

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