Question

SOMEONE, PLEASE HELP!!!!!!

Answer 1

Answer:

I think its y^-3

Step-by-step explanation:

Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3

then using rules of exponents you would subtract the exponents witch would be y^-3

Answer 2

Answer:

$\frac{1}{y^{3} }$

Step-by-step explanation:

$\frac{y^{-5}}{y^{-2}}$

Apply exponent rule $\frac{x^a}{x^b}=x^{a-b}$

$=y^{-5-\left(-2\right)}$

Apply rule $-\left(-a\right)=a$

$=y^{-5+2}$

Add/Subtract the numbers -5+2=-3

$=y^{-3}$

Apply exponent rule $a^{-b}=\frac{1}{a^b}$

$=\frac{1}{y^3}$