1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly_w [17]
3 years ago
12

Emily is encouraged to read more than 4 hours each week. It takes her 45 minutes to finish her first book. She divides the remai

nder of the time equally amongst the other six days. What is the minimum number of minutes she should read each day? Write and solve an inequality.
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

32 mins 50 seconds

Step-by-step explanation:

Total number of hours to read weekly \geq 4

she has read for 45 minutes, so she has 4 hrs - 45 minutes = 3 hrs 15 minutes left

Dividing the time equally = 195 mins / 6

minimum number of minutes to read \geq 32 minutes 50 seconds

You might be interested in
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
3 years ago
Explain how to solve this problem:
galina1969 [7]

"every dollar" means P = 1

compounded monthly interest means 12

1(1+(.129/12)^(12(1)) =

in calculator do pemdas

1. .129/12 = 0.01075

2. 0.01075 + 1 = 1.01075

3. (1.01075)^12 = 1.136907156 =

answer = 1.14

Mayfield schools

lcps

7 0
2 years ago
A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di
denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
3 years ago
Read 2 more answers
3/8 + 1/8 - 1/3 + 1/4 =
Dahasolnce [82]

Answer:

0.41666666, to round up, the answer is 0.42

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
How many times dose 28 go into 6
Ivan

6 goes 4 times into 28 because 6 x 4 = 24

3 0
3 years ago
Read 2 more answers
Other questions:
  • If the following two triangles are similar, find X.<br><br> Show work please
    13·1 answer
  • How do I solve this question?
    8·2 answers
  • What is the value of the expression 1 – r – a when r = 20 and a = 6?
    15·2 answers
  • Kamisha is planning to conduct a survey at her school. She has decided to interview 7 out of 30 students. If there are 510 stude
    8·1 answer
  • Because the numerator and denominator of the fraction are equivalent, the value of the fraction is __________ o Multiplying by 1
    13·1 answer
  • A desk is on sale for $135.20, which is 26% of the regular price. What is the regular price?​
    5·1 answer
  • Simplify the expression.<br><br> 8(5k + 6m)
    8·2 answers
  • A dressmaker needs to cut 9-inch pieces of ribbon from rolls of ribbon that are 9 feet in length. How many 9-inch pieces can the
    13·1 answer
  • HELP ITS FOR A TEST
    5·2 answers
  • If x2 = 20. what is the value of x? <br>sqrt 10 <br>sqrt 20 <br>10 <br>40​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!