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posledela
3 years ago
10

How many cups of ketchup would 13 hamburgers get if there was 3 1/4 cups of ketchup to be equally split among the 13 burgers? (i

just copied the question from my paper)
Mathematics
1 answer:
Setler [38]3 years ago
6 0
.25 cups of ketchup for each hamburger
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8578.76  dollars.

Step-by-step explanation:your welcome :) please give brainliest

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WILL MARK BRAINLIEST!!! A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel
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3 years ago
Write 2x+3y=6 in slope intercept form
Leokris [45]
Slope-intercept form:
y=mx+b

m=slope
b=y-intercept

2x+3y=6
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3 years ago
Help me out some one
Olegator [25]
Y = mx + b is the slope-intercept form of the equation of a line,
where m = slope, and b = y-intercept.

In problems 1 and 3, your equations are written in the y= mx + b form, so you can read the slope and y-intercept directly.

1.
m = -5/2
b = -5

3.
m = -1
b = 3

5.
For problem 5, you need to solve for y to put the equation
in y = mx + b form. Then you can read m and b just like we did
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7 0
3 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
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