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3 years ago

Please Help y’all

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

7 0

Answer:WHAT DID U GET FOR THIS PLZZZZZZZZZZZz

Step-by-step explanation:

help

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Remember that $\sin(\theta) = \cos(90^\circ - \theta)$

Thus, we can solve for x.
x + 22 = 90 - (2x - 7)
x + 22 = 97 - 2x
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3 years ago

Solve the equation by multiplying by a power of 10. 3.1x - 10 = 1.6x + 35

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3 years ago

Which letter has rotational symmetry? Answer Choices: 1. B 2. R 3. J 4. I

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4 years ago

I really need help if anyone can help that would be great

Oliga [24]

Factor the denominator:

(3x-1)(x+2)

every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.

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the answer here is C.

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4 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

3 years ago