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3 years ago

What is the class boundary between the first and second classes?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

7 0

Answer:

Wealth

Step-by-step explanation:

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The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by

siniylev [52]

Answer:

the value of x=33

the measure of each base angle = 42 ,69,69

Step-by-step explanation:

Bases od isosceles triangles are congruent,so

2(2x+3)=4x+6 (This is the sum ob both anlgles base)

All angles in a triangle add to 180

4x+6 + 42 = 180

4x = 132

x=33

2(33)+3= 69

69+69+42 = 180

5 0

3 years ago

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Help plz i give brainliest

Natasha_Volkova [10]

Answer: Hope this helps :)

$\frac{1}{5} b^{27}$

<h2>Mark me as Brainliest please</h2>

6 0

2 years ago

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Which of the following represents a polynomial expression? Select one: A. 2x + 3log(x) + 5 B. 10x−−√ − 2 C. (x + 1)(x - 1) D. 4x

Mnenie [13.5K]

Answer:

none!

Step-by-step explanation:

5 0

3 years ago

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If × = 2,y =-6 and z =4.Find the value of 4z + 2y-x.

serg [7]

Answer:

The answer is 2

Step-by-step explanation:

4z+2y-x

4(4)+2(-6)-2

16+(-12)-2

16-12-2

4-2

8 0

3 years ago

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how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

3 years ago