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Margarita [4]
3 years ago
9

What is the class boundary between the first and second classes?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

Wealth

Step-by-step explanation:

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The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by
siniylev [52]

Answer:

the value of x=33

the measure of each base angle = 42 ,69,69

Step-by-step explanation:

Bases od isosceles triangles are congruent,so

2(2x+3)=4x+6 (This is the sum ob both anlgles base)

All angles in a triangle add to 180

4x+6 + 42 = 180

4x = 132

x=33

2(33)+3= 69

69+69+42 = 180

5 0
3 years ago
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Help plz i give brainliest
Natasha_Volkova [10]

Answer: Hope this helps :)

\frac{1}{5} b^{27}

<h2><u><em>Mark me as Brainliest please</em></u></h2>
6 0
2 years ago
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Which of the following represents a polynomial expression? Select one: A. 2x + 3log(x) + 5 B. 10x−−√ − 2 C. (x + 1)(x - 1) D. 4x
Mnenie [13.5K]

Answer:

none!

Step-by-step explanation:

5 0
3 years ago
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If × = 2,y =-6 and z =4.Find the value of 4z + 2y-x.​
serg [7]

Answer:

The answer is 2

Step-by-step explanation:

4z+2y-x

4(4)+2(-6)-2

16+(-12)-2

16-12-2

4-2

2

8 0
3 years ago
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how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}
icang [17]

Answer:

\int\limits {e^{2s} cos\frac{s}{4} ds    =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that  f(s) =  e^{2s} cos\frac{s}{4}

Now integrating

            \int\limits {f(s)} \, ds =  \int\limits {e^{2s} cos\frac{s}{4} ds

By using integration formula

   \int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2}  } ( a cos b x + b sin b x )

<u><em>Step(ii):-</em></u>

 \int\limits {e^{2s} cos\frac{s}{4} ds    =   \frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2}  } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4}  sin \frac{1}{4}  s ))  

                    = \frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4}  sin \frac{1}{4}  s ))

                   = \frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s}{4}  ))

                 = 16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s}{4}  ))

                 =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

<u><em>Final answer:-</em></u>

\int\limits {e^{2s} cos\frac{s}{4} ds    =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

6 0
3 years ago
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