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3 years ago

Which expression is equivalent to (–3y – x) – (5y – 8x)?

Mathematics

2 answers:

Lorico [155]3 years ago

8 0

I hope this helps.

-8y+7x

olga55 [171]3 years ago

6 0

Answer:

$7x-8y$

Step-by-step explanation:

We have been given an expression $(-3y-x)-(5y-8x)$ . We are supposed to simplify our given expression.

Using distributive property $a(b+c)=ab+ac$ , we will get:

$-3y-x-1*5y-1*-8x$

$-3y-x-5y+8x$

Now, let us combine like terms.

$-x+8x-5y-3y$

$7x-8y$

Therefore, the simplified form of our given expression would be $7x-8y$ .

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What is the solution set for the equation 2|-3n| + 10 = 50<br><br> I

Aleks04 [339]

Answer:

$n=-\frac{20}{3}\quad \mathrm{or}\quad \:n=\frac{20}{3}$

Step-by-step explanation:

$2\left|-3n\right|+10=50\\\\\mathrm{Subtract\:}10\mathrm{\:from\:both\:sides}\\\\2\left|-3n\right|+10-10=50-10\\\\Simplify\\\\2\left|-3n\right|=40\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{2\left|-3n\right|}{2}=\frac{40}{2}\\\\Simplify\\\\\left|-3n\right|=20\\\\\mathrm{Apply\:absolute\:rule}:\\\quad \mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a\\$

$-3n=-20\quad \mathrm{or}\quad \:-3n=20\\\\-3n=-20\quad :\quad n=\frac{20}{3}\\\\-3n=20\quad :\quad n=-\frac{20}{3}\\\\n=-\frac{20}{3}\quad \mathrm{or}\quad \:n=\frac{20}{3}$

5 0

3 years ago

Find the sum.<br><br> (8x^4+2x^2−1) + (3x^3−5x^2+7x+1)

natka813 [3]

Answer: 8x⁴ + 3x³ -3x² + 7x

6 0

3 years ago

Read 2 more answers

Given: ΔPSQ, PS = SQ

horrorfan [7]

<h2>Answer:</h2>

To solve this problem we will use Heron's formula:

$A=\sqrt{s(s-a)(s-b)(s-c)}$

Where $a, \ b \ and \ c$ are the side lengths of the triangle and $s$ is the semiperimeter (half the perimeter of the triangle). We know that:

$Perimeter \ P=\triangle PSQ=PS+PQ+SQ: \\ \\ \triangle PSQ=P=50 \\ \\ Semiperimeter \ s: \\ \\ s=\frac{P}{2}=25$

Also:

$(I) \ PS=SQ \\ \\ (II) \ SQ-PQ = 1 \\ \\ (III) \ PS+PQ+SQ=50 \\ \\ \\ (I) \ into \ (III): \\ \\ SQ+PQ+SQ=50 \\ \\ \therefore (IV) \ 2SQ+PQ=50 \\ \\ From \ (II): \\ \\ PQ=SQ-1 \\ \\ (II) \ into \ (IV): \\ \\ 2SQ+(SQ-1)=50 \\ 3SQ-1=50 \\ 3SQ=51 \\ \\ \boxed{SQ=17} \\ \\ \boxed{PS=17} \\ \\ PQ=SQ-1=17-1 \therefore \boxed{PQ=16}$

Finally:

$A=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ A=\sqrt{s(s-PS)(s-SQ)(s-PQ)} \\ \\ A=\sqrt{s(s-17)(s-17)(s-16)} \\ \\ A=\sqrt{25(25-17)(25-17)(25-16)} \\ \\ \boxed{A=120}$

7 0

3 years ago

(9r - 5 ) - ( -4r + 9 ) Can you subtract the expression

Elis [28]

Answer:

13R - (-14)

Step-by-step explanation:

I believe this is the right answer i really hope it is im sorry if its wrong

Have a good day!

4 0

3 years ago

Read 2 more answers

Prove that:

Likurg_2 [28]

Step-by-step explanation:

16⁴ - 2¹³ - 4⁵

= 2¹⁶ - 2¹³ - 2¹⁰

= 2¹⁰(2⁶ - 2³ - 1)

= 2¹⁰(64 - 8 - 1)

= 2¹⁰ * 55

= 2¹⁰ * 5 * 11.

Since it contains 11 in its prime factorization, it is divisible by 11. (Proven)

3 0

3 years ago