Question

PLEASE HELP FOR A BRAINLIEST!!!! Create your own example and explain how to solve Quadratic Equation using Quadratic Formula. What part in the Quadratic Formula is the discriminant and how do you know the number of solutions based on the value of the discriminant? Pls pls help I need YALLS brains

Answer 1

Step-by-step explanation:

1. Create your own example and explain how to solve Quadratic Equation using Quadratic Formula.

The quadratic formula is used to solve quadratic equations. It is shown as   $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

A quadratic equation is generally shown in the form of $ax^{2} +bx + c = 0$

For example, if you saw the equation  $7x^{2} + 3x + 20 = 0$

7 would be $a$, 3 would be $b$, and 20 would be $c$.

To solve the equation above, you would fill in the quadratic formula as such, $x=\dfrac{-3\pm\sqrt{(3)^2-4(7)(20)}}{2(7)}$

Then you could solve for x.

2. What part in the Quadratic Formula is the discriminant?

The discriminant is the equation under the square root on the quadratic formula, $b^{2} - 4ac$

It is tells us whether there are two solutions, one solutions, or no solutions.

3.  How do you know the number of solutions based on the value of the discriminant?

To know the number of solutions based off of the value of the discriminant, you need to plug in your values. Using the example quadratic equation, $7x^{2} + 3x + 20 = 0$

We will plug the values into the discriminant.

$3^{2} - 4(7)(20) = -551$

Now, if the discriminant is positive it has two real solutions. If the discriminant is zero the equation has no real-number solutions. And finally, if the discriminant is negative, the equation has one real solution. Because our discriminant is -551, the example equation has one real solution.

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