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timama [110]
3 years ago
7

Select the correct product.

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

Option A. 2x^{3}+7x^{2}+12x-8

Step-by-step explanation:

we have

(x^{2}+4x+8)(2x-1)

Applying the distributive property

(x^{2}+4x+8)(2x-1) =x^{2}(2x)-x^{2} +4x(2x)-4x+8(2x)-8\\ \\=2x^{3}-x^{2} +8x^{2}-4x+16x-8\\ \\= 2x^{3}+7x^{2}+12x-8

You might be interested in
Distributive property of 8 x 31
solong [7]
Your answer would be 248
7 0
3 years ago
Solve for x.<br><br> 2/3(x−7)=−2
zaharov [31]
2/3x - 14/3 = -2
3(2/3x - 14/3) = -2(3)
           2x - 14 = -6
                   2x = -6 + 14
                   2x = 8
                     x = 8/2
                     x= 4

hope this helps :)



5 0
3 years ago
Read 2 more answers
Pls help i beg i will give brainlist and points
leonid [27]

Answer:

7. 1/10 or 10%

9.5/10

11.5/10

13.9/10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
There is 5/6 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1/6 of the pie that was left. How much of the whole
Lady_Fox [76]
5/6 = 83% 
1/6= 16%

83% of the apple pie was left from dinner. 
Victor is gonna eat 16% of the pie tomorrow 
You have to subtract 16% from 83%
In other words 5/6-1/6


The denominators are same so you don't have to do anything to them  
5/6 - 1/6 

5-1=4

4/6 of the pie would be left 
In simplest form it would be 

4/6     <span> ÷2</span>
=2/3

2/3 is in simplest form 

5 0
3 years ago
Read 2 more answers
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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