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Rufina [12.5K]
3 years ago
14

During week one of his training Conrad did 10 push-ups every day. He increased his daily number of push-ups by 5 every week afte

r that. How many push-ups did Conrad do every day during week 25?
Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
He starts with 10, +5 after every week
week 2=10+5
week 3=10+5*2
...
week 25 =10+5*24
f(x)=10+5(x-1)
so during the 25th week=10+5*24=10+120=130
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What is the sum of a 56-term arithmetic sequence where the first term is 6 and the last term is 391?
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S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\a_1=6;\ n=56;\ a_{56}=391\\\\subtitute\\\\S_{56}=\dfrac{6+391}{2}\cdot56=\dfrac{397}{2}\cdot56=397\cdot28=11,116
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3 years ago
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I need help simplifying these radicals. someone please help!!
Andrej [43]

First one: 60\sqrt{7}

Second one: 160\sqrt{3}

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David, a platform diver, dives into the pool during practice. The height of David above the water at any given time, s, can be m
ella [17]

Check the pictures below.

if we knew the roots/solutions of the equation, we can set h(s) = 0 and solve for "s" to find out how many seconds is it when the height is 0.

if you notice in the first picture, when f(x) = 0, is when the parabola hits a root/solution or the ground, for David he'll be hitting the water surface, and the equation that has both of those roots/solutions conspicuous is

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4 0
3 years ago
Jonah runs 3/5 miles on Sunday and 7/10 miles on Monday.He uses the model to find that he ran a total of 1 mile. What mistake do
antoniya [11.8K]

Answer: He did not convert the fractions into the like fraction to add.


Step-by-step explanation:

Given: The distance Jonah runs on Sunday= \frac{3}{5} miles

The distance Jonah runs on Monday= \frac{7}{10} miles

The total distance he ran = \frac{3}{5}+\frac{7}{10}\ miles

Since both the fractions are not like , thus multiply 2 to the numerator and the denominator of the first fraction [to add fractions first convert them into like fractions], we get

The total distance he ran = \frac{3\times2}{5\times2}+\frac{7}{10}\ miles

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The right answer is "The total distance he ran =1\frac{3}{10}\ miles"


7 0
3 years ago
The cost of staying in a hotel is given by the formula C=50d+20, where C is the cost in £ and d is the number of days a person s
Fynjy0 [20]

Answer:

a) £320

b) £720

c) 2 days

Step-by-step explanation:

The question is all about inputting values and finding a result or rearranging and finding a result.

a) d = 6. C = 50(6)+20      = 320

b) d = 2x7 (7 days a week)  C = 50(2x7) + 20     = 720

c) C = 120 ... 120 = 50d+20

100 =50d      d = 100/50      = 2

3 0
2 years ago
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