Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!
Answer:
0
Step-by-step explanation:
8+56/-7x-4
8+(-8)x-4
0x-4
0
Hope this helps ;) ❤❤❤
Answer:
C
Step-by-step explanation:
![7^{\tfrac 14} = \sqrt[4]{7}](https://tex.z-dn.net/?f=7%5E%7B%5Ctfrac%2014%7D%20%3D%20%5Csqrt%5B4%5D%7B7%7D)
C
Because that is what you do first