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3 years ago

Can someone help me please:)(picture below)

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Because it's a parellelogram, we can assume DH and HF are parallel, and we can assume GH and HE are parallel. Set DH and HF equal to each other to solve for x, and GH and HE equal to each other to solve for y. You would use system of equations.

Solving for y:
x + 3 = 3y
x=3y-3

2x-5=5y+2
2(3y-3)-5=5y+2
6y-6-5=5y+2
6y-11=5y+2
y=13

Solving for x:
x+3=3y
y=(1/3)x+1

2x-5=5y+2
2x-5=5((1/3)x+1)+2
2x-5=(5/3)x+5+2
2x-5=(5/3)x+7
2x=(5/3)x+12
(1/3)x=12
x=36

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3 years ago

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4 years ago

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Lesechka [4]

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3 years ago

Read 2 more answers

Need Help With Functions. Screenshot attatched

FinnZ [79.3K]

Answer:

4x² -29x +51

Step-by-step explanation:

Put x-3 where x is in the original function definition, then "simplify". I think you'll find it convenient to rewrite the original function definition first.

... g(x) = 4x² -5x = x(4x -5)

Substituting, we have

... g(x-3) = (x -3)(4(x -3) -5)

... = (x -3)(4x -17) . . . . . simplify right factor

... = 4x² -12x -17x +51

... g(x -3) = 4x² -29x +51

3 0

3 years ago