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serg [7]
4 years ago
8

Jonah runs 3/5 miles on Sunday and 7/10 miles on Monday.He uses the model to find that he ran a total of 1 mile. What mistake do

es Jonah make
Mathematics
1 answer:
antoniya [11.8K]4 years ago
7 0

Answer: He did not convert the fractions into the like fraction to add.


Step-by-step explanation:

Given: The distance Jonah runs on Sunday= \frac{3}{5} miles

The distance Jonah runs on Monday= \frac{7}{10} miles

The total distance he ran = \frac{3}{5}+\frac{7}{10}\ miles

Since both the fractions are not like , thus multiply 2 to the numerator and the denominator of the first fraction [to add fractions first convert them into like fractions], we get

The total distance he ran = \frac{3\times2}{5\times2}+\frac{7}{10}\ miles

=\frac{6}{10}+\frac{7}{10}=\frac{6+7}{10}\\\\=\frac{13}{10}=1\frac{3}{10}\ miles

The right answer is "The total distance he ran =1\frac{3}{10}\ miles"


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3 years ago
Barry and Kerrie are discussing their pets
ss7ja [257]

Based on the statements provided, Barry will a have a Labrador, a Collie and a Staffie at home if he has at least one dog breed.

<h3>What is logical reasoning ?</h3>

Logical reasoning in mathematics is the process of using rational and critical thinking abilities to arrive at a conclusion about a problem.

Since Barry have at least one dog breed, the possible breeds of dogs that Barry have can be determined as follows:

Statement 1: If I have a Labrador but not a Staffie, I also have a Collie

Statement 2: I either have both a Collie and a Staffie or neither.

Statement 3: If I have a Collie, then I also have a Labrador.

  • From Statement 1, If Barry will have a Labrador and Collie if he doesn't have a Staffie.
  • From Statement 2, Barry will have both a Collie and a Staffie or he wont have either.
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Therefore, Barry will have a Labrador, a Collie and a Staffie at home if he has at least one dog breed.

Learn more about logical reasoning at: brainly.com/question/25175983

7 0
2 years ago
Peter is renting two kinds of rafts for a vacation company. One type seats 3
Nady [450]

Answer:

Peter rents 6 of the rafts seating 3 people, and 7 of the rafts seating 5 people.

Step-by-step explanation:

Let x denote the number of rafts seating 3 people and y the number of rafts seating 5 people. The total number of rafts is 13, so x+y=13. We can also assume that every raft is filled to the brim (it isn't stated explicitly though, but it's probably the intention of the question maker), so 3x+5y=53.

It's always a good idea to put these equations under each other:

\left \{ {{x+y = 13} \atop {3x+5y=53}} \right.

We can subtract the first equation three times from the second one to obtain (3x+5y)-3(x+y) = 53 - 3(13)\\3x-3x + 5y - 3y = 53 - 39\\2y = 14\\y=\frac{14}{2} = 7

Now, substitute this found value for y into x+y = 13 and we see that x=6. We are now done: Peter rents 6 of the rafts seating 3 people, and 7 of the rafts seating 5 people.

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But that piece is cut out of the bottom.  The cut-out piece is 3cm wide and 3cm high, so its area is 3x3= 9 cm².

9 cm²  have been cut out of the 45 cm²  of the complete big rectangle.  So the remaining area of the figure is  45 - 9 =<em> 36 cm²</em> .

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