The guy above me has it right!
Answer:
m∠J = 45° , m∠I = 45° and m∠M = 90°
And the ΔJIM is an isosceles right angled triangle.
Step-by-step explanation:
(a). In ΔJIM,
∠J = 2x + 15,
∠I = 5x - 30, and
∠M = 6x
Now, using angle sum property of a triangle that sum of all the angles in a triangle is 180°
⇒ ∠J + ∠I + ∠M = 180°
⇒ 2x + 15 + 5x - 30 + 6x = 180°
⇒ 13x -15 = 180°
⇒ 13x = 195
⇒ x = 15
Therefore, m∠J = 45° , ∠I = 45° and m ∠M = 90°
(b). Now, ΔJIM is a right angled triangle right angled at M.
Also, ∠J = ∠I = 45°
So, JM = IM ( because in a triangle sides opposite to equal angles are equal)
So, ΔJIM is an isosceles triangle because its two sides are equal.
Hence, ΔJIM is a right angled isosceles triangle right angled at M.
Draw a diagram to illustrate problem as shown below.
Let h = the height of the tree.
Because ΔABC ~ ΔADE, therefore
DE/BC = AD/AB
That is,
h/1.94 = (5.1 + 10.2)/5.1 = 3
h = 1.94*3 = 5.82 m
Answer: 5.82 m
Answer:
h = -5*t +800
Step-by-step explanation:
The initial value is 800 ft
She is falling at a rate of 5 ft per second
That would be -5ft/s
We can write this in the form
y = mx+b
h = -5*t +800 where t is the number of seconds and h is the height above ground
