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Ivahew [28]
4 years ago
12

Please help with this problem. I keep getting -25

Mathematics
1 answer:
katrin [286]4 years ago
4 0
\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}
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Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.

  • sinA = opposite/hypotenuse
  • cosA = adjacent/hypotenuse
  • tanA = opposite/adjacent

Now that we know three basic ratio. Let's check each choices!

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This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.

  • sin50° = c/x

This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.

  • tan50° = d/c

This choice is correct! As ratio states, tanA = opposite/adjacent.

  • tan50° = x/c

This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.

  • cos50° = x/d

This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.

  • cos50° = c/x

This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.

Answer

  • tan50° = d/c
  • cos50° = c/x

Questions can be asked through comment.

Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.

Hope this helps, and Happy Learning! :)

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