The experimental probability of the arrow stopping on Section 2 will be 
. is the ratio of the favorable event to the total number of events.
<h3>What is probability?</h3>
Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.
No of arrows given in the different section ;
Section 1=18
Section 2=30
Section 3=32
The probability that the arrow stopping on Section 2 is found as;
Hence, the experimental probability of the arrow stopping on Section 2 will be .
More about the probability link is given below.
brainly.com/question/795909
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First of all I want to point out you drew the diagram a little wrong. The Arc is 41 doesn't mean its 41 degrees it means it has length 41 so remove the degrees symbol.
Now for the answer the other arc have to have angle 40 too because vertical angles. And because the radius is the same, both of the length has formula 40/360*pi*2*radius which is 41 in this case. So x has to be 41 also :) Done!
Answer: f(x)=1-1.9x=x-2
Step-by-step explanation:
Big brain time.
Answer: exact form: 7/5
Decimal form: 1.4
Mixed form: 1 2/5
Step-by-step explanation:
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
