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fomenos
4 years ago
5

Please show/explain how you found the answer

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
3 0
H=3.4s- start with the problem
20=3.4s- substitute the known number(s)
20/3.4=3.4/3.4 s- divide both sides by 3.4
The answer is about 5.88, your answer should be between 5 and 6
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SBC is an isosceles triangle with main vertex S.
stira [4]

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

4 0
2 years ago
On a coordinate plane, 2 polygons are shown. Polygon A B C D is larger than polygon A prime B prime C prime D prime and is refle
Stells [14]

The similarity transformation is a dilation with a scale factor less than 1 and then a reflection

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Dilation is the increase or decrease in the size of a figure by a scale factor.

Polygon ABCD is larger than polygon A'B'C'D' and is reflected across the y-axis to form polygon A'B'C'D'

The similarity transformation is a dilation with a scale factor less than 1 and then a reflection

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

5 0
2 years ago
Find the square root of following by division method<br> 5499025
Sedbober [7]
The answer to your question is 2345
4 0
2 years ago
Read 2 more answers
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean \mu =266\\

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find P(X\geq 308)

Using normal distribution,

z=\frac{X-\mu}{\sigma}

z=\frac{308-266}{15}

=\frac{42}{15}

Thus z=2.8

So P\left (X\geq 308  \right )=1-P(X

=1-P(z

=1-Table\:  value\:  of\:  2.8

=1-0.99744

=0.00256

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3​%.

The z-value for the lowest of 3% is -1.8808

Then X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu

This implies X=-1.8808*15+266=237.788

Thus the babies who are born on or before 238 days are considered to be premature.

5 0
3 years ago
Find value of x round answer to nearest tenth
Aloiza [94]

Answer:

14

Step-by-step explanation:

19^2 = y^2+ 17^2

y = 8.5

by figure

x = 31 - 2*y

x = 14

4 0
2 years ago
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