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Zielflug [23.3K]
3 years ago
14

On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 2) and (4, 0). Everything below and to t

he left of the line is shaded. Which point is a solution to the linear inequality y < Negative one-halfx + 2? (2, 3) (2, 1) (3, –2) (–1, 3)

Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

Option C.

Step-by-step explanation:

A dashed straight line has a negative slope and goes through (0, 2) and (4, 0).

The given inequality is

y

We need find the point which is a solution to the given linear inequality.

Check the given inequality for point (2, 3).

3

3    

This statement is false. Option 1 is incorrect.

Check the given inequality for point (2, 1).

1

1

This statement is false. Option 2 is incorrect.

Check the given inequality for point (3, -2).

-2

-2

This statement is false. Option 3 is correct.

Check the given inequality for point (-1,3).

3

3

This statement is false. Option 4 is incorrect.

Therefore, the correct option is C.

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What is the area of rectangle with length 18cm and width 4cm?
miv72 [106K]
I hope this helps you




Area=width×length



Area=18×4



Area=72
5 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
[-1/4/5] × [-7/10+0.95] - [-2/1/4]
const2013 [10]

Answer:

-2.5625

Step-by-step explanation:

<u>1)[-1/4/5] × [-7/10+0.95] - [-2/1/4] turn that into improper fractions</u>

2 1/4=9/4

which is 1 4/5(-7/10+0.95)9/4

<u>2) 1 4/5(-7/10+0.95)= 0.3125</u>

which is 0.3125-9/4

<u>3)Make into decimal form</u>

9/4 equals 2.25

which is 0.3125-2.25

which all equals -2.5625

5 0
3 years ago
Three cubic feet of seawater weigh 192 pounds.
sweet-ann [11.9K]

Answer:

<em>3731.2 pounds</em>

Step-by-step explanation:

<em>Aquarium will hold 4.4 * 2.5 * 5.3 = 58.3 cubic feet of sea water.</em>

<em>For 3 cubic feet of sea water, weight is 192 pounds</em>

<em>For 58.3 cubic feet of sea water,</em>

<em>( 192 * 58.3) / 3 = 11193.6 / 3 = 3731.2 pounds</em>

6 0
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Answer:

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Help the mother earth please

8 0
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