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Papessa [141]
3 years ago
12

One of the factors x^2+3x-10

Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0
Factor the equation
(x+5)(x-2)

Check
5-2=3
5*-2=-10
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Mary invests £12000 in a savings account. The account pays 1. 5% compound interest per year. Work out the value of her investmen
mestny [16]

Answer:

The value of Mary's investment after two years = £12362.7

Step-by-step explanation:P = Principal / initial amountR = rate of interest per cent per yearT = number of yearsA = final amount at the end of T yearsThen:A = P*(1 + R/100)^2In our example:P = £12000R = 1.5 per cent per yearT = 2 yearsThus:A = 12000*(1 + 1.5/100)^2   = 12000*(1 + 0.015)^2   = 12000*(1.015)^2    = 12000*(1.030225)    = 12362.7Value of investment after two years = £12362.7

4 0
2 years ago
What value of x solves the equation? -3(-5x + 4) = -6​
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Answer:

X = 2/5

Step-by-step explanation:

By the way.

does February March?.... NO but April May

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3 years ago
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What is the domain of the<br> quadratic parent function y=x2?
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\Large \boxed{\mathrm{All \ real \ numbers}}

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y=x^2

The domain are the set of all possible values for x.

There are no restrictions on the value of x.

The domain is all real numbers.

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For the data set below, which of the
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Please anyone to show me how this mathematics question is done..please
irinina [24]

9514 1404 393

Answer:

  (i) 55.59 km/h

  (ii) 3600 nautical miles ≈ 6670.8 km

  (iii) 30°N 29.3°E

Step-by-step explanation:

(i) The speed in km/h requires a units conversion.

  (30 kt/h)(1.853 km/kt) = 55.59 km/h

__

(ii) Here, we assume we're interested in the <em>distance traveled</em>. If the course is "due east", we presume that means it follows the 30° latitude line, so is not the shortest route between A and B. That is, the distance from A to B will be different from the distance traveled. (The shortest route from A to B is along a great circle.)

  distance = speed × time

  distance = (30 kt/h)(120 h) = 3600 nautical miles

  = (55.59 km/h)(120 h) = 6670.8 km

__

(iii) The radius of the 30° latitude line is ...

  (6370 km)(cos(30°)) = 3185√3 km ≈ 5516.58 km

The relationship between arc length (s) and central angle (α) is ...

  s = rα

So, the change in the vessel's longitude is ...

  α = (6670.8 km)/(5516.58 km) ≈ 1.20923 radians ≈ 69.28°

Then town B has longitude ...

  40°W -69.3° = -29.3°W = 29.3°E

The position of town B is about 30°N 29.3°E.

_____

<em>Additional comment</em>

The route supposedly taken by this sea vessel is from the middle of the North Atlantic to a town in northern Egypt, through the northern Sahara desert. The eastern end point is shown in the attachment.

Some spherical trigonometry is involved if you want to find the end point of the great-circle route of the same length.

5 0
2 years ago
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