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Sholpan [36]
3 years ago
12

The second term in a geometric sequence is 12. The fourth term in the same sequence is 4/3. What is the common ratio in this seq

uence?
Mathematics
2 answers:
aniked [119]3 years ago
3 0
The common ratio in this sequence is 6:2 or 4:3
Lapatulllka [165]3 years ago
3 0

Answer:

The common ratio is r=\pm\frac{1}{3}.

Step-by-step explanation:

Given : The second term in a geometric sequence is 12. The fourth term in the same sequence is 4/3.

To find : What is the common ratio in this sequence?

Solution :

The nth term of G.P is a_n=ar^{n-1}

The second term in a geometric sequence is 12.

i.e. a_2=ar^{2-1}

12=ar .....(1)

The four term in a geometric sequence is \frac{4}{3}.

i.e. a_4=ar^{4-1}

\frac{4}{3}=ar^3 .....(2)

Divide (1) and (2),

\frac{\frac{4}{3}}{12}=\frac{ar^3}{ar}

\frac{1}{9}=r^2

\sqrt{\frac{1}{9}}=r

\pm\frac{1}{3}=r

Therefore, the common ratio is r=\pm\frac{1}{3}.

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