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3 years ago

8

I need some help with sequences

1 answer:

Maslowich3 years ago

7 0

Sequences are based off of the directions, if it is least to greatest it is the smallest number, if you can't figure it out it is the farthest on the left of a number line the the farthest on the tight. If it is greatest to least, it is the biggest number first and the smallest last, if you can't figure that out it is the farthest on the right to the farthest on the left.

1. It is adding 5 each time so the next two are 31,36

2. Same thing 28,33

All you have to do is find the sequence I between them. Hope this helps!

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F(x)=ax+b/2 then f^-1 (x-1) =2x-5/2 find a and b

krok68 [10]

From the given inverse function, we have

$f^{-1}(x-1) = 2x - \dfrac52 \\\\ \implies f^{-1}(x) = f^{-1}((x+1)-1) = 2(x+1) - \dfrac52 = 2x-\dfrac12$

By definition of inverse function,

$f\left(f^{-1}(x)\right) = x$

so that

$f\left(2x-\dfrac12\right) = x$

$a\left(2x-\dfrac12\right) + \dfrac b2 = x$

$2ax - \dfrac a2 + \dfrac b2 = x$

$\implies\begin{cases}2a=1 \\\\ -\dfrac a2+\dfrac b2 = 0\end{cases}$

$\implies \boxed{a=\dfrac12}$

$\implies \dfrac b2 = \dfrac a2 \implies \boxed{b=\dfrac12}$

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2 years ago

Find the mean, median, mode, and range of the following data.

Elena-2011 [213]

Mean (average) - add all numbers up and divided by the number of addends

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Median = 35

Mode - number that appears the mode

Mode = 80

Range - difference between biggest and smallest number

Range = 80

~theLocoCoco

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3 years ago

wolverine [178]

(1.)
Would be the correct answer because you can't add the two values together, they both need to have 'x' to be able to.

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Solve the problem.

Alex73 [517]

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nordsb [41]

Answer:

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