coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
y=2
Step-by-step explanation:
Make an equation of straight line by using the formula :y= mx+c
put the x-value of point (2,4) which is 2 and the gradient,m which is 2 into the straight line equation:
y=2x +c
So you need to find the y-intercept to complete the equation, therefore:
when y=0,
0=2(2)+c
c=-4
next the question ask to find the y-coordinate when x =3, therefore you just need to replace x in the equation with 3:
y=2(3)-4
y=4
Answer:
A. x < 6 and x > - 28
Step-by-step explanation:
We have been given the following inequality;
| x+11 | < 17
We can replace the absolute value function by re-writing the inequality as;
-17< x+11<17
subtract 11 from both sides;
-17-11<x+11-11<17-11
-28<x<6
splitting this we have;
x<6
x>-28
It is not 90 degrees it is 87
