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3 years ago

Determine if -10,-12,or -16is the solution of 2t-2=26

1 answer:

3 0

2t-2=26
first you would add 2 to both sides
that equals 2t=28
then you would divide both sides by two
that would give you
t= 14

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Dominik [7]

The answer is $2.50 because you do 145-132.50=12.5
Then you divide by 5 because that’s the difference between students then the final answer is 2.50

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3 years ago

Find the percent of increase from 15 to 20

ANEK [815]

I think it might be 25%

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3 years ago

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Clarissa has a budget of $1,200 a month to spend for rent and food. She has already spent $928 this month. Which inequality repr

shtirl [24]

Answer:

1200-928 = 272 for the rest of the month Clarissa has to spend.

Step-by-step explanation:

So we don't want her to go over her budget so we wouldn't choose a greater than option for her so eliminate the first option and the last option. Now we just have the middle two. We want to keep it under 1200 but theres nothing wrong with spending that exact amount each month so I would pick x less than or equal to 272, since we can still equal the total of less than the total and not go over. Option 2 or B.

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3 years ago

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Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

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3 years ago

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Rama09 [41]

Answer:

work is shown and pictured

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