All categories

3 years ago

How would you figure the number of protons or electrons in an atom

1 answer:

8 0

The number of protons in an atom can be determined by the element's atomic number, and the number of electrons can be determined by subtracting by atomic mass by the atomic number.

You might be interested in

Cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

MAXImum [283]

<3333333333333333 >>:)))

Explanation:

5 0

2 years ago

Read 2 more answers

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl

diamong [38]

Answer:

For A: The average molecular speed of Ne gas is 553 m/s at the same temperature.

For B: The rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

Explanation:

For A:

The average molecular speed of the gas is calculated by using the formula:

$V_{gas}=\sqrt{\frac{8RT}{\pi M}}$

$V_{gas}\propto \sqrt{\frac{1}{M}}$

where, M is the molar mass of gas

Forming an equation for the two gases:

$\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}$ .....(1)

Given values:

$V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol$

Plugging values in equation 1:

$\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s$

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

For B:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

$Rate\propto \frac{1}{\sqrt{M}}$

Where, M is the molar mass of the gas

Forming an equation for the two gases:

$\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}$ .....(2)

Given values:

$Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol$

Plugging values in equation 2:

$\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr$

Hence, the rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

8 0

2 years ago

Which of the following describes the relationship between acid strength and ka value for weak acids?

Leona [35]

I think the correct answer would be when ka increases, the acid strength increases. Ka is the product of hydronium ions and the [A-] ions concentration over the acid concentration. Therefore, increasing the the Ka, the numerator in the definition would increase as well which correspondingly increase the strength of the acid.

8 0

3 years ago

1.20g of methyl alcohol, CH3OH, are dissolved in 16.8g of water, H2O. What is the mole fraction of the solute?

kolezko [41]

Answer:

0.0386

Explanation:

To make a solution, we need a certain amount of the solute to be dissolved in the solvent. The solvent is the carrier medium usually water in traditional wet chemistry.

Now, in this particular question, it should be known that methyl alcohol is the solute, while water is the solvent.

We need to calculate the mole fraction of the solute as asked by the question. Now what we do is to find the number of moles of each, add together, then divide the number of moles of methyl alcohol by the sum of the moles of both.

Firstly, we calculate the number of moles of methyl alcohol present. This is mathematically equal to dividing mass by molar mass

Molar mass of methyl alcohol (CH3OH) is 12 + 4(1) + 16 = 32g/mol

The number of moles is thus 1.2/32 = 0.0375 moles

Now, we calculate the number of moles of water. The molar mass of water is 18g/mol

The number of moles of water is thus 16.8/18 = 0.93333

The mole fraction of the solute is thus:

0.0375/(0.0375 + 0.9333) = 0.0386

7 0

3 years ago

Read 2 more answers

The combination of isotopes of hydrogen characterized by emmision of radiation is believed to take place in the

kaheart [24]

I think the answer is star

3 0

3 years ago