Answer:
5.39 g
Explanation:
The balanced equation for the reaction of aluminum with hydrochloric acid is shown below as:-
Given,
Pressure = 0.750 atm
Temperature = 30.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (30.0 + 273.15) K = 303.15 K
T = 303.15 K
Volume = 10.0 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.750 atm × 10.0 L = n × 0.0821 L.atm/K.mol × 303.15 K
⇒n = 0.3013 moles
Moles of hydrogen obtained = 0.3013 moles
From the reaction,
3 moles of hydrogen gas are furnished when 2 moles of aluminum is consumed.
Also,
1 mole of hydrogen gas are furnished when mole of aluminum is consumed.
Thus,
0.3013 mole of hydrogen gas are furnished when mole of aluminum is consumed.
Moles of aluminum consumed = 0.2 moles
Also, Molar mass of aluminum = 26.981539 g/mol
So, Mass = Moles*Molar mass = 0.2 moles*26.981539 g/mol = 5.39 g
Answer:The IUPAC name of compound would be Hex-3-yn-ol
Explanation:
When butyne is treated with LDA it leads to generation of carbanion on the terminal alkyne.
As LDA is disopropyl amide which happens to be quite a good base and hence it is sufficiently basic to abstract the acidic proton on the terminal alkyne.
So this proton abstraction leads to generation of a carbanion which can now acts as a nucleophile in step 2.
In step 2 the generated carbanion attacks the strained epoxide ring to open the strained epoxide ring .The product of step 2 leads to generation of hex-3-yn-1-olate
Further on treating the product formed in step 2 with the dilute acid it leads to the formation of alcohol as the negative charge on oxygen can now be neutralised.
Kindly refer the mechanism for structure of compounds.