7/28 is the answer to your question.
I wish I could help but I didn’t learn that
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
Answer: 18 units
Step-by-step explanation:since its is a horizontal line x2 - x1
7 -1 = 6
line 2:
since this is a vertical line y2 - y1
7 - 3 = 4
line 3:
since this is a horizontal line x2 - x1
7 - 4 = 3
line 4:
for this we need to use the distance formula which allows us to find the distance making a third point to form a right angle triangle
point 1: (1,3)
point 2: (4,7)
point 3 (new point) : (4,3)
now we can apply the pythogorean thereum (C squared = B squared + A squared) with the following lines.
line 1: (1,3) - (4,7)
line 2: (1,3) - (4,3)
line 3: (4,3) - (4,7)
line 1 squared = line2 squared + line 3 squared
calculate length of line 2 and 3
line 1 squared = (4 - 1) squared + (7 - 3) squared
line 1 squared = 3 squared + 4 squared
line 1 squared = 9 + 16
line 1 squared = 25
root both sides
line 1 = 5
add all the liens together
6 + 4 + 3 + 5 = 18