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Alex777 [14]
3 years ago
12

10. RECREATION In a game of kickball, Rickie has to kick the

Mathematics
1 answer:
wel3 years ago
4 0

Answer:

The angle Rick must kick the ball to score is an angle between the lines BX and BZY which is less than or equal to 32°

Step-by-step explanation:

The given measures of the of the angle formed by the tangent to the given circle at X and the secant passing through the circle at Z and Y are;

m\widehat{XZ}  = 58^{\circ}

m\widehat{XY}  = 122^{\circ}

The direction Rick must kick the ball to score is therefore, between the lines BX and BXY

The angle between the lines BX and BXY = ∠XBZ = ∠XBY

The goal is an angle between m\widehat{XY}

Let 'θ' represent the angle Rick must kick the ball to score

Therefore the angle Rick must kick the ball to score is an angle less than or equal to ∠XBZ = ∠XBY

By the Angle Outside the Circle Theorem, we have;

The angle formed outside the circle = (1/2) × The difference of the arcs intercepted by the tangent and the secant

\therefore \angle XBZ = \dfrac{1}{2} \times \left (m\widehat{XY}  -m\widehat{XZ} \right)

We get;

∠XBZ = (1/2) × (122° - 58°) = 32°

The angle Rick must kick the ball to score, θ = ∠XBZ ≤ 32°

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hey, can someone please double check these questions for me / or help me solve them if they are incorrect? thank you U-U ​
zzz [600]

Question 11

The directrix is a horizontal line, which means the parabola opens either upward or downward. In this case, it opens downward. This is because all answer choices have a negative leading coefficient. Also, it's because the focus is below the directrix.

For vertically opening parabolas, we use this form

4p(y-k) = (x-h)^2

where (h,k) is the vertex and p is the focal distance, aka the distance from the vertex the focus. To find (h,k), we start at the focus (0,-4) and move directly up until we reach the directrix y = 4. We'll arrive at (0,4). The midpoint of (0,-4) and (0,4) is (0,0) which is the vertex's location. So (h,k) = (0,0).

Note that in moving from (0,-4) to (0,4) is a span of 4 units. So this is the value of p.

Plug h = 0, k = 0, p = 4 into the equation mentioned and solve for y

4p(y-k) = (x-h)^2

4*4(y-0) = (x-0)^2

16y = x^2

y = (1/16)x^2

The only adjustment we need to make is to change the 1/16 to -1/16 so that the parabola opens downward.

<h3>Answer:  Choice D.  y = -(1/16)x^2</h3>

===============================================

Question 3

The given equation is in the form y = ax^2+bx+c

In this case,

  • a = 2
  • b = 4
  • c = 3

Let's compute the x coordinate of the vertex h

h = -b/(2a)

h = -4/(2*2)

h = -1

This h value is plugged into the original function to find k

f(x) = 2x^2+4x+3

f(-1) = 2(-1)^2+4(-1)+3

f(-1) = 1

We find that h = -1 and k = 1 pair up together. In short, (h,k) = (-1,1) is the vertex.

<h3>Answer: Choice B.  (-1,1)</h3>
8 0
3 years ago
A student wants to estimate the mean score of all college students for a particular exam. First use the range rule of thumb to m
Wewaii [24]

Answer:

See explanation below

<u>Step-by-step explanation:</u>

range = 2200 - 300 = 1900

To find standard deviation, we have:

standard deviation = range/4 = \frac{1900}{4} = 475

The range rule of thumb estimate for the standard deviation is 475

Given:

Standard deviation,\sigma = 475

Margin of Error, ME = 100

\alpha = 1 - 0.90 = 0.10

Za/2 = Z0.05 = 1.64

Find sample size, n:

n ≥ [Z_\alpha_/_2 * (\frac{\sigma}{ME})]^2

n ≥ [1.64 * (\frac{475}{100})]^2

n ≥ 60.68

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Minimun sample size,n = 61

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3 years ago
What is the value of the expression below?
lukranit [14]

Answer:

D. 30

Step-by-step explanation:

-5(-8)(3)(-1) /(-4)

Lets simplify the numerator first

-5*-8 = 40

40 *3 = 120

120*-1 = -120

Replace -5(-8)(3)(-1)  with -120

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8 0
3 years ago
.......................
hodyreva [135]

Answer:

1) when tomato patch is 6.5 feet the area is 191.75 sq.ft

2)  when tomato patch is 7 feet the area is 217 sq.ft

3) when area is 338 sq.ft the tomato patch is 9.0778 feet

4) when area is 147.25 sq.ft the tomato patch is 5.543799 feet

Step-by-step explanation:

The given equation is  :

3x^2 + 10x

Length of Tomato (in feet)                                       x,  6.5   ,  x   ,     7

Patch Area of Vegetable Garden (in square feet) 338, x , 147.25, x

So we can find the missing terms with the help of the equation 3x^2 + 10x

Putting the values of x from the length of the tomato patch

1)  3x^2 + 10x= 3(6.5)²+ 10 (6.5)=126.75+ 65= 191.75 square feet

2) 3x^2 + 10x= 3(7)² +10 (7)= 147+70= 217 square feet

So the area of  her vegetable garden for a variety of  lengths of the tomato patch= 6.5 feet is 191.75  square feet

and for 7 feet is 217 square feet

Similarly we can find the length of the tomato patch from the area by again using the given equation  3x^2 + 10x

So when area = 338 square feet

The equation becomes  

3x^2 + 10x= 338

Rearranging it :     3x^2 + 10x-338 =0

This is a quadratic equation and can be solved with the help of the formula.

Here a= 3, b= 10 and c= -338

x = -b±√b²- 4ac/2a

Putting the values of a,b,c we get

x= -10±√100+ 4056/6

x= -10± 64.467/6

x= 54.467/6 or -74.467/6   we ignore the negative value because the garden cannot have the negative area.

x= 9.0778 feet

Similarly repeating the same process would give

So when area = 147.25 square feet

The equation becomes  

3x^2 + 10x= 147.25

Rearranging it :     3x^2 + 10x-147.25 =0

This is a quadratic equation and can be solved with the help of the formula.

Here a= 3, b= 10 and c= - 147.25

x = -b±√b²- 4ac/2a

Putting the values of a,b,c we get

x= -10±√100+ 1767/6

x= -10± 43.208/6

x= 33.208/6 or -53.208/6  we ignore the negative value because the garden cannot have the negative area.

x= 5.543799 feet

6 0
3 years ago
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