Given the equation 2 square root x-5=2 solve for x and identify if it is an extraneous solution
2 answers:
<span>2√(x-5) = 2
</span><span>√(x-5) = 1
</span>x-5 = 1
x=6(I don't know what extraneous solution means though)
Answer: 2√(x-5) = 2
√(x-5) = 1
x-5 = 1
x=6 solution is not extraneous!
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