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hammer [34]
3 years ago
9

Given the equation 2 square root x-5=2 solve for x and identify if it is an extraneous solution

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0
<span>2√(x-5) = 2
</span><span>√(x-5) = 1
</span>x-5 = 1
x=6(I don't know what extraneous solution means though)
liraira [26]3 years ago
7 0

Answer: 2√(x-5) = 2

√(x-5) = 1

x-5 = 1

x=6 solution is not extraneous!

You might be interested in
Find a power series for the function, centered at c, and determine the interval of convergence. f(x) = 9 3x + 2 , c = 6
san4es73 [151]

Answer:

\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ........

The interval of convergence is:(-\frac{2}{3},\frac{16}{3})

Step-by-step explanation:

Given

f(x)= \frac{9}{3x+ 2}

c = 6

The geometric series centered at c is of the form:

\frac{a}{1 - (r - c)} = \sum\limits^{\infty}_{n=0}a(r - c)^n, |r - c| < 1.

Where:

a \to first term

r - c \to common ratio

We have to write

f(x)= \frac{9}{3x+ 2}

In the following form:

\frac{a}{1 - r}

So, we have:

f(x)= \frac{9}{3x+ 2}

Rewrite as:

f(x) = \frac{9}{3x - 18 + 18 +2}

f(x) = \frac{9}{3x - 18 + 20}

Factorize

f(x) = \frac{1}{\frac{1}{9}(3x + 2)}

Open bracket

f(x) = \frac{1}{\frac{1}{3}x + \frac{2}{9}}

Rewrite as:

f(x) = \frac{1}{1- 1 + \frac{1}{3}x + \frac{2}{9}}

Collect like terms

f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2}{9}- 1}

Take LCM

f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2-9}{9}}

f(x) = \frac{1}{1 + \frac{1}{3}x - \frac{7}{9}}

So, we have:

f(x) = \frac{1}{1 -(- \frac{1}{3}x + \frac{7}{9})}

By comparison with: \frac{a}{1 - r}

a = 1

r = -\frac{1}{3}x + \frac{7}{9}

r = -\frac{1}{3}(x - \frac{7}{3})

At c = 6, we have:

r = -\frac{1}{3}(x - \frac{7}{3}+6-6)

Take LCM

r = -\frac{1}{3}(x + \frac{-7+18}{3}+6-6)

r = -\frac{1}{3}(x + \frac{11}{3}+6-6)

So, the power series becomes:

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}ar^n

Substitute 1 for a

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}1*r^n

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}r^n

Substitute the expression for r

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}(-\frac{1}{3}(x - \frac{7}{3}))^n

Expand

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}[(-\frac{1}{3})^n* (x - \frac{7}{3})^n]

Further expand:

\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ................

The power series converges when:

\frac{1}{3}|x - \frac{7}{3}| < 1

Multiply both sides by 3

|x - \frac{7}{3}|

Expand the absolute inequality

-3 < x - \frac{7}{3}

Solve for x

\frac{7}{3}  -3 < x

Take LCM

\frac{7-9}{3} < x

-\frac{2}{3} < x

The interval of convergence is:(-\frac{2}{3},\frac{16}{3})

6 0
3 years ago
How many prime numbers are there between 45 and 72?
laila [671]
There are 47,51,53,59,61,67,71, that is, 7 primes.
4 0
3 years ago
Read 2 more answers
write the linear equation from the given information in slope intercept form passing through (-2,8) and perpendicular to y=2x+5​
Leto [7]

Answer:

y  =  -\frac{1}{2} x + 9

Step-by-step explanation:

Given parameters:

  Coordinates = (-2,8)

Equation of the line  y  = 2x + 5;

Unknown:

Linear equation of a line perpendicular = ?

Solution:

From the given expression, a line perpendicular will have a negative inverse of the slope given.

           y  = 2x + 5

Equation of a line  is y = mx + c;

y and x are the coordinates

  m is the slope

   c is the intercepts

    y  = 2x + 5 ;

 The slope is 2;

  A line perpendicular will have a slope of -\frac{1}{2}  

 Since y = 8 and x  = -2, let us find c;

     8  = 2 x -\frac{1}{2}  + c

    8 = -1 + c

     c  = 8+1 = 9

The equation of the line is;

       y  =  -\frac{1}{2} x + 9

7 0
3 years ago
I need help please I’m confused
Ilia_Sergeevich [38]
143/80 = 1 63/80 (use cymath!! it helps!!)
3 0
3 years ago
It says to find the value of X, having a hard time understanding how to do this one.
andreyandreev [35.5K]

Answer:

First Area of the triangle=180 Degree

I,e ∠A+∠B+∠C=180°

Given ∠A= 21

          ∠B=34

          ∠C=X

∠A+∠B+∠C=180°

21+ 34+ x°=180°

55+x=180°

x°= 180-55

x= 125°

Step-by-step explanation:


6 0
3 years ago
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