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hammer [34]
2 years ago
9

Given the equation 2 square root x-5=2 solve for x and identify if it is an extraneous solution

Mathematics
2 answers:
umka2103 [35]2 years ago
7 0
<span>2√(x-5) = 2
</span><span>√(x-5) = 1
</span>x-5 = 1
x=6(I don't know what extraneous solution means though)
liraira [26]2 years ago
7 0

Answer: 2√(x-5) = 2

√(x-5) = 1

x-5 = 1

x=6 solution is not extraneous!

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PLEASE ASAP ILL GIVE YOU BRAINLIEST
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2 years ago
A rectangle and a square have the same area. The width of the rectangle is 2 in less than the side of the square and the length
lina2011 [118]
The area of a rectangle is A=LW, the area of a square is A=S^2.

W=S-2 and L=2S-3

And we are told that the areas of each figure are the same.

S^2=LW, using L and W found above we have:

S^2=(2S-3)(S-2)  perform indicated multiplication on right side

S^2=2S^2-4S-3S+6  combine like terms on right side

S^2=2S^2-7S+6  subtract S^2 from both sides

S^2-7S+6=0  factor:

S^2-S-6S+6=0

S(S-1)-6(S-1)=0

(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:

S=6 is the only valid value for S.  Now we can find the dimensions of the rectangle...

W=S-2 and L=2S-3  given that S=6 in

W=4 in and L=9 in

So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.


5 0
2 years ago
Two equations are given below: a – 3b = 9 a = b – 3 What is the solution to the set of equations in the form (a, b)?
Vilka [71]
A-3b=9
a=b-3

b-3-3b=9
-2b-3=9
-2b=12
2b=-12
b=-6

a=-6-3
a=-9

Solution: (-9,-6)
----
Check: 
-9=-6-3
-9=-9
TRUE


7 0
3 years ago
Read 2 more answers
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tino4ka555 [31]

Answer:

I believe b is 5.

Step-by-step explanation:

When you place the points in the values, you get 5=3(0)+b. When you simplify it, you get 5=b. I really hope this is correct, I apologize if it isn't! I hope this helps! :)

4 0
3 years ago
Read 2 more answers
Can somebody please help me with this question
Zanzabum

Answer:

B

Step-by-step explanation:

6 0
2 years ago
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