Answer:
(g+f)(x)=(2^x+x-3)^(1/2)
Step-by-step explanation:
Given
f(x)= 2^(x/2)
And
g(x)= √(x-3)
We have to find (g+f)(x)
In order to find (g+f)(x), both the functions are added and simplified.
So,
(g+f)(x)= √(x-3)+2^(x/2)
The power x/2 can be written as a product of x*(1/2)
(g+f)(x)= √(x-3)+(2)^(1/2*x)
We also know that square root dissolves into power ½
(g+f)(x)=(x-3)^(1/2)+(2)^(1/2*x)
We can see that power ½ is common in both functions so taking it out
(g+f)(x)=(x-3+2^x)^(1/2)
Arranging the terms
(g+f)(x)=(2^x+x-3)^(1/2) ..
1. <span>12(x − 4)
</span>2. <span>x5
</span>3. <span>The quotient of some number and ten
</span>4. <span>b − 8
</span>5. <span>The quotient of four times some number and six
</span>6. <span>3x + 7
1. x and -4 are multiplied by 12
2 raided to this 5th power is an exponent
3 quotient means division
4 less than means subtraction
5 division means quotient, list numerator first then the denominator
6 product of is multiplication and more is an addition.</span>
Answer:
x = 2
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for x
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
x² = 14² + 10² = 196 + 100 = 296
Take the square root of both sides
x = 
= 2
Answer:
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Step-by-step explanation:
