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mina [271]
3 years ago
15

In the first 3 3/4 hours of a marathon, Susan ran at an average speed of

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

0.125 miles per minute

Step-by-step explanation:

ran 3 miles: 9.5 min per mi × 3 mi = 28.5 minutes = 28 minutes, 30 seconds How to calculate running speed. Divide your run distance by your run time; If you ran 2.5 miles and you ran for 20 minutes: 2.5 mi ÷ 20 min = 0.125 miles per minute

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2 years ago
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Which animal traveled at a rate of 1.5 meters per minute?
Fofino [41]

Answer:

The ant

Step-by-step explanation:

We know that the meters traveled is going to be more than the amount of minutes because it is 1.5:1 so that narrows it down to the turtle and the ant.

Now we can just take 150% of each and see if they match up.

150% of 5 is 7.5 so therefore it is not the Turtle which means it must be the ant.

Hope this helped ! !

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3 years ago
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I don't understand how to solve?
Kobotan [32]
Ok u have a phone and call 911 and say I don't know to solve can u help me
6 0
4 years ago
Mr smith likes small oranges he likes to eat some everyday over the summer he will eat 3 oranges a day on the days with a “t” in
faltersainse [42]

Answer:

Step-by-step explanation:

Days with t are: Tuesday, Thursday and Saturday.

In the period of time given there are 20 T days (20 x 3 = 60 oranges)

In the period of time given there are ? no T days (27 x 2 = 54 oranges)

60 + 54 = 114 Oranges eaten over the school holidays

8 0
3 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
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