Question

Let ƒ(x) = 5x2 – x + 1 and g(x) = –3x. Evaluate the composition (ƒ ∘ g)(1) .

Answer 1

Answer:

D

Step-by-step explanation:

We are given the two functions:

$f(x) = 5x^2-x+1 \text{ and } g(x) = -3x$

And we want to find:

$(f \circ g)(1)$

Recall that this is equivalent to:

$=f(g(1))$

Evaluate g(1):

$g(1) = -3(1) = -3$

Substitute:

$=f(-3)$

Evaluate f(-3):

$f(-3)=5(-3)^2-(-3)+1=49$

Therefore:

$(f \circ g)(1) =49$

Our answer is D.

Answer 2

Answer:

49

Step-by-step explanation:

ƒ(x) = 5x2 – x + 1 and g(x) = –3x

(ƒ ∘ g)(1)

First find g(1) = -3(1) = -3

Then find f(g(1) = f(-3)

f(-3) = 5(-3)^2 - (-3) +1 = 5(9) +3+1 = 45+4 = 49