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3 years ago

Distributive property to simplify 64-16

Mathematics

2 answers:

koban [17]3 years ago

8 0

You can’t do that there’s no ()

nika2105 [10]3 years ago

4 0

^^^^^^^^^^^^^^^^^^^^^^^^^^^

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If you deposit $5,000 into an account that pays 4.75% annual interest how much money will be in the account after 7 years if the

victus00 [196]

$6662.50

4.75% = $237.50
$237.50 x 7 = $1662.50

$5000 + $1662.50 = $6662.50

Answer = $6,662.50

4 0

3 years ago

Please please help!!!! this is my last question! thank you!!!

BlackZzzverrR [31]

Answer:

B) 5

Step-by-step explanation:

Divide the volume by the formula and you get that 1000=r^3. r is 10, but every second it gains 2 cm, so divide 10 by 2 to get 5

6 0

3 years ago

A student knows the height of a pyramid and the area of its base. What should the student do to find the volume of the pyramid

Varvara68 [4.7K]

Answer:

Multiply the area of the base by the height and divide by 3.

Step-by-step explanation:

V = (1/3)Bh

where B = area of the base, and

h = height

Answer: Multiply the area of the base by the height and divide by 3.

5 0

3 years ago

Read 2 more answers

Sophia buys an apple that weighs 0.45 pound, a grapefruit that weighs pound, a navel orange that weighs pound, and a pear that w

Tanzania [10]

Answer:

The order of fruit from least to greatest weight is -

Apple , pear, navel orange, grapefruit

Step-by-step explanation:

P.S - The exact question is -

Given - Sophia buys an apple that weighs 0.45 pound, a grapefruit that weighs $\frac{3}{4}$ pound, a navel orange that weighs $\frac{5}{8}$ pound, and a pear that weighs 0.5 pound.

To find - What is the order of the fruit from least weight to the greatest weight ?

Proof -

Weight of apple = 0.45 pound

Weight of grapefruit = $\frac{3}{4}$ pound = 0.75 pound

Weight of navel orange = $\frac{5}{8}$ pound = 0.625 pound

Weight of a pear = 0.5 pound

As,

0.45 < 0.5 < 0.625 < 0.75

So, The order of fruit from least to greatest weight is -

Apple , pear, navel orange, grapefruit

8 0

3 years ago

if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length

jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0

3 years ago