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coldgirl [10]
3 years ago
10

A student factors a^6 - 64 to (a^2 - 4)(a^4 + 4a^2 + 16). Which statement about (a^2 − 4)(a^4 + 4a^2 + 16) is correct?

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
So that equation was definitely correct...

When you expand the equation in the bracket you'll find out that you'll get a^6 + 4a^4 + !6a^2 - 4a^4 - 16a^2 -64. then your final result will be a^6 - 64
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Jet001 [13]3 years ago
3 0

Answer:the expression is equivalent, but the (a^2-4) term in not completely factored.

Step-by-step explanation: just got it right on edgen

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The equation for the line of best fit is f(x) ≠1. 8x ⒠5. 4 for the set of values in the table. A 2-column table with 7 rows.
AleksandrR [38]

The equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

Given that

The equation for the line of best fit is f(x) = 1.8x − 5.4 for the set of values in the table.

A 2-column table with 7 rows.

The first column is labeled x with entries 4, 5, 6, 6, 8, 9, 10.

The second column is labeled f(x) with entries 5, 2, 5, 6, 8, 7, 18.

We have to determine

Using the equation for the line of best fit, what is a good approximation for x when f(x) = 30?

According to the question

The quadratic regression equation can be expressed as;

\rm f(x) = 1.8x - 5.4

Then,

The approximation for x when f(x) = 30 is,

\rm f(x) = 1.8x - 5.4\\\\\rm 30= 1.8x - 5.4 \\\\ 1.8x= 30+5.4\\\\1.8x=35.4\\\\x = \dfrac{35.4}{1.4}\\\\x=19.67\\\\x=20 \ approx

Hence, the equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

To know more about the Quadratic equation click the link given below.

brainly.com/question/26164308

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3 years ago
Explain how to do distributive property. Use an example.
klasskru [66]

Answer:

so we have 4(3x + 10)

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<h2>12x+40</h2>

Step-by-step explanation:

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4 years ago
My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
In-s [12.5K]

Answer:

Question 1) 17.4

Question 2) 1.7

Question 3) 2.8

Question 4) 8.6

Step-by-step explanation:

Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.

method to calculate Mean absolute deviation:

a. calculate mean

b. calculate absolute deviation of each data point

c. add all the deviations

d. divide absolute deviation by number of points

mean absolute deviation = ∑lx_{i}-xl / n

The given problem has four sub-parts

Solution 1:

Mean= (78+99+90+80+55+56+102+88+60+42)/10

            =  750/10

            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

                                             I 60-75 I + I 42-75 I) /10

         =  (174)/10

        =  17.4

Solution 2:

Mean = (10+13+7+12+9+8+12+10+11+13)/10

              =  (105)/10

              = 10.5

Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +

                                              I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +

                                               I 11-10.5 I + I 3-10.5 I) /10

       =   17/10

       = 1.7

Solution 3:

Mean= (1+7+10+5+3+3+6+12+9+4)/10

            =  60/10

            =  6

Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

         = (28)/10

        =  2.8

Solution 4:

Mean= (30+46+25+45+18+25+15+32+40+24)/10

            =  300/10

            =  30

Mean absolute deviation  = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +

                                               I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +

                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

!

8 0
3 years ago
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