3 years ago

What is the equation for the line with slope m=−4 and y-intercept b=3

1 answer:

5 0

Answer:

ok so i am going to give you a litle saying to help you remember the way it goes ok. this problem is in slope-intercept form

"y=mx+b,,b is my y-intercept you'll see,m is my slope which is rise over run"

so if -4 is your slope it will go where the m is in the formula y=mx+b so it would now be y=-4x+b and then the b is your y-intercept so 3 would go where the b is in the formula now now since we plugged in all the parts.

<u>the answer is y=-4x+3 </u>

Step-by-step explanation:

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4m-2+(-8m)<br> Need answer ASAP please help me

DENIUS [597]

Answer:

-4m-2 Hope I helped

Step-by-step explanation: Remove parentheses.

4m−2−8m

Subtract 8m

from 4m

−4m−2

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2 years ago

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A) ¿Cómo varia el volumen de una piramide en relación a su altura si el área de la base no cambia?

beks73 [17]

Answer:Step-by-step explanation:

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2 years ago

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Which number is the median? 5, 15, 16, 20, 21, 21, 23, 23, 23, 26, 26, 26, 26, 27, 27, 29, 29, 29, 29, 29, 30, 30, 30, 30

scoray [572]

Answer:

median is 26

Step-by-step explanation:

26+26=52

52÷2=26

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2 years ago

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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago

HELP ME PLEASE!!!!!!!!

ale4655 [162]

I think this is how you do it

4 0

2 years ago