Which equation represents this number sentence?<br> Two less than one-fourth of a number is 10.

A 2001 study by two researchers investigated an anti-poverty initiative in Venezuela called POVERTA. POVERTA gave money to poor

ANEK [815]

Answer:

1. This is a "RANDOMIZED CONTROLLED EXPERIMENT".

A randomized controlled experiment is a type of research study, were the researcher randomly select samples in other not to be biased. This samples are separated into two groups, which are the experimental and the controlled group.

2. The research has a treatment group and a controlled group.

A treatment group are those group that received some special treatment from the researcher, it can also be called the experimental group. According to the research, the treatment group are those who are in the POVERTA scheme. That is the 320 communities.

A controlled group are those group that were not given any special treatment, but are , separated and studied. According to the research the controlled group are those 185 communities

3. This research provides evidence that being in a community receiving POVERTA benefits is associated with a lower rate of childhood illness. Because after two years, it was noticed the children in the community that receives POVERTA has low rate of illness, than the children in a community that doesn't receive the benefits of POVERTA.

4. This study does not provide evidence that being in a community receiving POVERTA benefits causes a lower rate of childhood illness. Because the research did not involve treatment of illnesses and they is no experimental evidence that shows that POVERTA benefits is interrelated with illness, as illness involves the internal functions of human body.

5. Such study will be called a "RANDOMIZED CONTROLLED EXPERIMENT". Because their randomly isolated themselves, and the POVERTA treatment was not given to them. The researcher was not based in selecting them not to participate.

3 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

8 0

2 years ago

(Area of Composite Figures)Help me pls.

oksian1 [2.3K]

Answer:

69 centimeters squared

Step-by-step explanation:

First, find the area of the big square = 11cm * 4cm = 44cm

Next, find the area of the leftover square = 5cm * 5cm =25cm

Add them together to get 69 centimeters squared

Hopefully this helps - let me know if you have any questions!

6 0

2 years ago

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Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re

klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0

2 years ago

Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA

AleksAgata [21]

1. Start with ΔCIJ.

∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0

2 years ago

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Which equation represents this number sentence? Two less than one-fourth of a number is 10.