Answer:
M = 107 degrees
Step-by-step explanation:
JKM = PQR
J = P
J = 33
K = Q
K = 40
R = M
R = 107
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
3 cm
Step-by-step explanation:
Set up an equation that solves for the surface area, "112
" :
10(2)+10(2)+2x+2x+10x+10x = 112
20+20+4x+20x = 112
24x+40=112
24x=72
x=3
So, 3 cm.
