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iVinArrow [24]
3 years ago
14

100 POINTS!!!! PLZ HELP ME I HAVE TO HAND IT IN!!! plz answer and show all steps

Mathematics
1 answer:
qaws [65]3 years ago
7 0
Give me a minute. I’m trying to solve
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Solve for x.<br><br> 8x^2-3=2
Mazyrski [523]
(2^3x^2 -  3) -  2  = 0 \\ \\  Factoring:  \ 8x^2-5 \\ \\   8x^2 - 5  = 0 \\ \\  Add \ 5  \ to \ both \ sides \ of \ the \ equation : \\ \\ &#10;                      8x^2 = 5 \\ \\ Divide \ both \ sides \ of \ the \ equation \ by \ 8: \\ \\ &#10;                     x^2 =  \frac{5}{8}  = 0.625 \\ \\ \boxed{ x  =\pm  \sqrt 5/8}

Your answer: Option A
7 0
3 years ago
What's the verbal expression for 100-5n
Yuri [45]
Five times a number less than one hundred.
6 0
3 years ago
Read 2 more answers
I need help please no links I will report
stellarik [79]

Answer: $1.45

Step-by-step explanation:

We start by subtracting the change from how much she payed for.

d = dollars | g = goldfish

16d - 0.05d = 15.95d

Then we divide by the goldfish

\frac{15.95d}{11g} = 1.45d

Our answer is 1.45!

<u>Also, warning, the people who go into the comments saying to download something from bitly, do not do it. They are viruses and will not get the answer, please only report their answer and ignore them.</u>

7 0
3 years ago
You can ride your bike around your block twice and the whole neighborhood once in 10 minutes. You can ride your bike around your
Bond [772]
I THINK,4=31
1=?
(1*31)/4=x
X=31/4
X=7.75minute to ride around the neighborhood once
It may not be correct
6 0
2 years ago
HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
2 years ago
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