Answer:
x=5
Step-by-step explanation:
so to isolate the x you dived the -3 to both sides
so it will now be
x=5 because a negative times or divided by a negative equals a positive so to prove that x=5
-3(5)=-15
which is true
Step-by-step explanation:
a) f(4) = 7-2(4)
= -1
b) f(h) = 7-2(h)
= 7-2h
c) f(4) + f(h) = -1 +(7-2h)
= 6-2h
h = 3
d) f(3+h) = 7-2(3+h)
= 7-6-2h
= -1-2h
2h= -1
h = -1/2
p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
