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kotykmax [81]
3 years ago
5

Can anyone help please

Mathematics
2 answers:
Liula [17]3 years ago
8 0
The answer is yes. The triangles are congruent.

I measured them with a ruler and they are the same length.

Hope this helped! c:
olga55 [171]3 years ago
3 0
Yes angle A is congruent to angle B

This statement is true.
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24 in 4 years later this
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HELP QUICK PLEASE! 20 POINTS
victus00 [196]

Answer:

54%

Step-by-step explanation:

Percent increase = (new - original)/ original  * 100%

The new cost is 800 and the original cost is 520

Percent increase = (800-520)/520 *100%

                             = 280/520 * 100%

                              .538461538 * 100%

                               53.8461538 %

 Give the answer to 2 significant figures, means we round to the ones place

                                 54 %

                             

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What is 6^7= pls help me i really need this
sleet_krkn [62]

Answer:

279936

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLZ HELP PLZ HELP THANK YOU
Kaylis [27]

Answer:

option C is a the right answer ...

plz mark my answer as brainlist plzzzz vote me also so

5 0
3 years ago
Read 2 more answers
The function f(x) = x2. The graph of g(x) is f(x) translated to the right 3 units and down 3 units. What is the function rule fo
Kaylis [27]

The rule for g(x) is: f(x) = (x-3)^2-3

Step-by-step explanation:

Given function is:

f(x) = x^2

When a function f(x) is shifted right or left, b units the new function is written as:

f(x) = x

Shifting right

g(x) = f(x-b)

Shifting left

g(x) = f(x+b)

Similarly, when shifting up or down

g(x) = f(x)+b => Up\\g(x) = f(x) - b => Down

As our given function is shifted 3 units to the right, it will be written as:

f(x) = (x-3)^2

The function is when moved down 3 units, then

f(x) = (x-3)^2-3

Hence

The rule for g(x) is: f(x) = (x-3)^2-3

Keywords: Function transformation, Functions

Learn more about functions at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

5 0
4 years ago
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