Answer:
When x=4
P(x) =4 - 4(4)^2 + 4(4) -5
=4 - 4(16) + 16 -5
=4 - 64 +11
= -60 + 11
= -49
Answer:
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 12, \sigma = 3](https://tex.z-dn.net/?f=%5Cmu%20%3D%2012%2C%20%5Csigma%20%3D%203)
What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?
This is 1 subtracted by the pvalue of Z when X = 16. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{16 - 12}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B16%20-%2012%7D%7B3%7D)
![Z = 1.33](https://tex.z-dn.net/?f=Z%20%3D%201.33)
has a pvalue of 0.9082
1 - 0.9082 = 0.0918
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated
180 of 72% is 129.6. 180*72= 12960. Since 72% = .72, you need to put the decimal 2 places behind the decimal.
![\boxed{x=3}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D3%7D)
Step-by-step explanation:
The Standard Form of the equation of line is given by:
![Ax+Bx=C \\ \\ For \ A, \ B, \ C\ Real \ Constant \\ and \ A>0](https://tex.z-dn.net/?f=Ax%2BBx%3DC%20%5C%5C%20%5C%5C%20For%20%5C%20A%2C%20%5C%20B%2C%20%5C%20C%5C%20Real%20%5C%20Constant%20%5C%5C%20and%20%5C%20A%3E0)
So:
![6x+y=18 \\ \\ is \ written \ in \ standard \ form](https://tex.z-dn.net/?f=6x%2By%3D18%20%5C%5C%20%5C%5C%20is%20%5C%20written%20%5C%20in%20%5C%20standard%20%5C%20form)
The x-intercept can be found setting
:
![6x+(0)=18 \\ \\ Isolating \ x: \\ \\ 6x=18 \\ \\ \boxed{x=3}](https://tex.z-dn.net/?f=6x%2B%280%29%3D18%20%5C%5C%20%5C%5C%20Isolating%20%5C%20x%3A%20%5C%5C%20%5C%5C%206x%3D18%20%5C%5C%20%5C%5C%20%5Cboxed%7Bx%3D3%7D)
<h2>Learn more:</h2>
Parabola: brainly.com/question/10605728
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