Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
1 = 3
2 = 6
3 = 9
Step-by-step explanation:
for every # it is multiplied by 3 (ex. 7 • 3 = 21, 8 • 3 = 24, ect.)
therefore if it is multiplied by 3 each time
then 1 • 3 = 3
2 • 3 = 6
and 3 • 3 = 9
hope this helps :)
Answer:
where are the graphs?
Step-by-step explanation: