115>5.75x+28.75
5.75x+28.75<115
5.75x<115-28.75
5.75x<86.25
x<86.25/5.75
x<15 or (-∞,15)
Answer: x<15 or (-∞,15)
Answer:
Option D (8,4)
Step-by-step explanation:
we know that
The dilation centered at the origin (0,0) is very simple. To find out the image point multiply the scale factor to the x and y-coordinates of the pre-image point.
so
(2*4,2*2) -----> (8,4)
Answer:
D) 1188 in.^2
Step-by-step explanation:
33×36 is 1188, the triangle on the side doesn't matter because it can be used to make the rectangle a whole rectangle, which means that the only important numbers are 33 and 36 multiplied to find the area, which is 1188^2.
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
First find the area of the parallelogram
Area of parallelogram = b x h
= 12 x 7
= 84
Then find area of kite
Area of kite = (xy)/2
= (7 x 12)/2
= 84/2
= 42
Now we are gonna subtract the area of the kite from the area of the parallelogram.
84 - 42 = 42
Therefore the area of the shaded region is 42.
