Ask question

Ask question

All categories

4 years ago

12

A taxicab starts at (1,-2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks we

st and 5 blocks north to drop off the passenger. What are the coordinates of the point where the passenger was dropped off?

1 answer:

Jobisdone [24]4 years ago

4 0

The coordinates of the drop off would be (-2,2)

You might be interested in

81.3 x 47.5 = i am lost............

Drupady [299]

Answer:

3861.75

Step-by-step explanation:

i hope its the good answer

5 0

3 years ago

it takes someone 15 minutes to prepare 3 1/4 cups of juice how many hours would it take to prepare 32 1/2 cups of juice

wariber [46]

$\bf \begin{array}{ccll} minutes&\stackrel{juice}{cups}\\ \cline{1-2} 15&3\frac{1}{4}\\\\ x&32\frac{1}{2} \end{array}\implies \cfrac{15}{x}=\cfrac{3\frac{1}{4}}{32\frac{1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{3\cdot 4+1}{4}}{\frac{32\cdot 2+1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{13}{4}}{\frac{65}{2}}$

$\bf \cfrac{15}{x}=\cfrac{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 65 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{15}{x}=\cfrac{1}{10}\implies 150=x\leftarrow \begin{array}{llll} \textit{150 minutes or}\\\\ \textit{2 hours and a half} \end{array}$

4 0

3 years ago

Solve the absolute value inequality

Anvisha [2.4K]

Absolute value= opposite. (positive turns into negative)(negative turns into positive)

4 0

3 years ago

ASAP! I really need help with this question! No nonsense answers, and please attach the solution.

uysha [10]

Answer:

$\boxed{\sf Option \ 4}$

Step-by-step explanation:

$\sqrt{2x-3} +x=3$

Subtract x from both sides.

$\sqrt{2x-3} +x-x=-x+3$

$\sqrt{2x-3}=-x+3$

Square both sides.

$( \sqrt{2x-3})^2 =(-x+3)^2$

$2x-3=x^2-6x+9$

Subtract x²-6x+9 from both sides.

$2x-3-(x^2-6x+9 )=x^2-6x+9-(x^2-6x+9)$

$-x^2 +8x-12=0$

Factor left side of the equation.

$(-x+2)(x-6)=0$

Set factors equal to 0.

$-x+2=0\\-x=-2\\x=2$

$x-6=0\\x=6$

Check if the solutions are extraneous or not.

Plug x as 2.

$\sqrt{2(2)-3} +2=3\\ \sqrt{4-3} +2=3\\\sqrt{1} +2=3\\3=3$

x = 2 works in the equation.

Plug x as 6.

$\sqrt{2(6)-3} +6=3\\ \sqrt{12-3} +6=3\\\sqrt{9} +6=3\\3+6=3\\9=3$

x = 6 does not work in the equation.

5 0

4 years ago

Read 2 more answers

Let f(x)=2(4)x+1−2. The graph of f(x) is translated 7 units to the left to form the graph of g(x).

ladessa [460]

This is what the following graph would look like:

5 0

3 years ago