O

Solve for m.<br><br> 5m+72=−2m+52

Tom [10]

M=-20/7. .........!!!!!!!!

6 0

3 years ago

Read 2 more answers

A bar of soap weighs as much as 3/4 of an identical bar plus 3/4 of a pound. How much does the bar of soap weigh?

Advocard [28]

3/4=0.75
Since 3/4 (of the bar) + 1/4 (of the bar) equals a whole bar (1), and 3/4 (of the bar) + 0.75 equals the whole weight of the bar, 0.75 is 1/4 of the bar. 1/4 times 4 equals 1, and 0.75 times 4 equals 3, so the bar of soap weighs 3 pounds.

5 0

3 years ago

2. Name the numerator and the denominator in each fraction.

marishachu [46]

Answer:

Step-by-step explanation:

a.11/12 =11 is numerator and 12 is denominator

b.7/512 =75 is numerator and 512 is denominator

c.12/10 = 12 is numerator and 10 is denominator

d0/78 = 0 is numerator and 78 is denominator

point to remember : In fraction,upper part is always numerator and down part is denominator.

6 0

2 years ago

THE GRAPH IS BELOW THANKS :) Anika is on the crew to set up rides for the state fair. The crew does most of the setup on the day

Vaselesa [24]

Answer:

(a) We will form an equation of line from the points given (6,10) and (2,15)

Using: $y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)$

On substituting the values in the formula above we will get the required equation of line.

$y-10=\frac{15-10}{2-6}\cdot (x-6)$

$\Rightarrow y-10=\frac{5}{-4}\cdot (x-6)$

On simplification we will get:

$y=\frac{1}{4}(-5x+70)$

(b) We need to tell at day 0 put x=0 in above equation:

$y=\frac{1}{4}(-5\cdot 0+70)$

$y=70$

Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.

Now, we need to tell decrease per day which is equal to the slope of line

To find the slope compare the equation with general equation which is y=mx+c where m is slope

Here, in $y=\frac{1}{4}(-5x+70)$

$m=\frac{-5}{4}$ which is the decrease per day.

3 0

3 years ago

What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

2 years ago