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rewona [7]
3 years ago
5

How to write the number 0.02 less than 1.423

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0
Less than means Subtract so,
0.02 less than 1.423 is 1.423-
0.02 which Equals 1.403
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X^2 + 5x - 24 = 0 How do I solve by factoring
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Answer:

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Step-by-step explanation:

To factor ax² + bx + c, use AC method.

a times c is 1 × -24 = -24.

Factors of ac (-24) that add up to b (5) are 8 and -3.

Divide by a and reduce: 8/1 and -3/1.

Therefore, the factors are x + 8 and x − 3.

x² + 5x − 24 = 0

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Please need help urgent
Scrat [10]
Answers with explanations:

Problem 2-
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3 0
3 years ago
Write a cosine function that has an amplitude of 5, a midline of 2 and a period of \frac{2\pi}{5} 5 2π ​ .
vlabodo [156]

Answer:

f(x) = 5*cos(5*x) + 2

Step-by-step explanation:

A general cosine function is written as:

f(x) = A*cos(ω*x) + M

where:

A is the amplitude

M is the midline

ω is the angular frequency.

In this case we know that:

The amplitude is 5, then A = 5

The midline is 2, then M = 2

The period is 2*pi/5

The relation between the angular frequency ω and the period T is:

ω = 2*pi/T

Then if the period is T = 2*pi/5, replacing that in the above equation we find that:

ω = 2*pi/T = 2*pi/(2*pi/5) = 5

ω = 5

Then the function is:

f(x) = 5*cos(5*x) + 2

7 0
3 years ago
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