20 less than (-20) a number (n) is more than (>) twice the same number (2n)
-20+n>2n
minus n both sides
-20>n
n<-20
Bolts are usually classified in terms of two types of measurements: the metric system and the imperial system. In calipers, the metric system is in units of millimeters, while the imperial system is in units of inches. For example, when a bolt is sized as 12 × 1.25 in the metric system, that means the bolt thread diameter measures 12 mm, and the thread pitch measures 1.25 mm.
So, if your metric bolt measures 0.78 over the threads, that means that the
size of the bolt is 0.78 mm in thread pitch. The attached picture shows how you measure the thread pitch.
Let's solve for x first,
3x + 5y - 5y = 1 - 5y
3x/3 = 1/3 - 5y/3
x = 1/3 - 5/3y
Let's now plug that into the other equation,
7(1/3 - 5/3y) + 4y = -13
7/3 - 35/3y + 4y = -13
7/3 - 7 2/3y - 7/3 = -13 - 7/3
- 7 2/3y (-3/23) = -15 1/3 (-3/23)
y = 2
The answer is 2
In grade 7, 10/18 students are members of the band.
In grade 8, 10/12 students are members of the band.
Because 10/12>10/18, the answer is B
Answer:
Total area of figure = [3x² + 7x + 6] feet²
Step-by-step explanation:
By dividing both rectangle by vertical line;
Given:
Length of big rectangle = (x + 3) feet
Width of big rectangle = (x + 2) feet
Length of small rectangle = 2x feet
Width of small rectangle = (x + 1) feet
Find:
Total area of figure
Computation:
Area of rectangle = Length x width
Total area of figure = Area of big rectangle + Area of small rectangle
Total area of figure = [(x + 3)(x + 2)] + [(2x)(x + 1)]
Total area of figure = [x²+ 2x + 3x + 6] + [2x² + 2x]
Total area of figure = [3x² + 7x + 6] feet²