Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
Total magic cakes =300
chocolate cakes =90
so if you want the percentage of chocolate you will divide the number of chocolate cakes over the total number of chocolates
% of chocolate cakes = 90/300×100%
=30%
(1 gal, 2 qt, 3 pt) +
(1 gal, 3 qt, 7 pt) +
(1 gal, 3 qt, 3 pt)
= (3 gal, 8 qt, 13 pt)
= (3 gal, 14 qt, 1 pt)
= (6 gal, 2 qt, 1 pt)
The total volume of punch is 6 gallons, 2 quarts, 1 pint, or 6 5/8 gallons.
Answer:
I have solved this problem on paper (Find pictures attached)
Answer:
es tal vez otra vez se repite la pregunta
